Question

I’m using XSLT to restructure an XML file. The following code copies all child nodes to a new XML file:

<!--Add all child elements of the zzz node--> <xsl:template match='zzz'>     <Trade>         <xsl:attribute name='ID'>             <xsl:value-of select='TradeId' />         </xsl:attribute>         <xsl:copy-of select='*'></xsl:copy-of>     </Trade> </xsl:template> 

I would like to modify the code so that it puts the nodes into a specific namespace that is not in the source document. What do I need to change?

Answer 1

The previous two answers (by teun and Craig Bovis) are not correct — see my comments to each of these.

The corect way to move a given element to a new namespace involves re-creating this element as shown below:

<xsl:stylesheet version='1.0'  xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>  <xsl:output omit-xml-declaration='yes' indent='yes'/>      <xsl:template match='zzz'>       <trade ID='{TradeId}'>         <xsl:apply-templates select='*[not(self::TradeId)]'/>       </trade>     </xsl:template>      <xsl:template match='zzz/*'>       <xsl:element name='{name()}' namespace='my:Trade'>         <xsl:copy-of select='@* | node()'/>       </xsl:element>     </xsl:template> </xsl:stylesheet> 

When this transformation is applied on the following source XML document:

<zzz>     <TradeId>153</TradeId>     <x:item xmlns:x='x:x'>A</x:item>     <x:item xmlns:x='x:x'>B</x:item>     <x:item xmlns:x='x:x'>C</x:item> </zzz> 

the required result is produced:

<trade ID='153'>    <x:item xmlns:x='my:Trade'>A</x:item>    <x:item xmlns:x='my:Trade'>B</x:item>    <x:item xmlns:x='my:Trade'>C</x:item> </trade>