Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7622155
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 31, 20262026-05-31T04:22:52+00:00 2026-05-31T04:22:52+00:00

I’m using yamlbeans to deserialize yaml files into Java objects. This works fine as

  • 0

I’m using yamlbeans to deserialize yaml files into Java objects. This works fine as long as I only have one class. The problem is when I want to nest a field, I am forced to specify the nested class in the yaml description.

Single class example:

Java:

public class MessageField {
    public String name;
    public String type;
    public int length;
    public String comment;
}

yaml:

name: field1
type: int
length: 4
comment: first field
---
name: field2
type: string
length: 16
comment: second field
---

Multiple classes (requires !com.mylib.VariableField in yaml file)

Java:

public class MessageField {
    public String name;
    public String type;
    public int length;
    public String comment;
    public List<VariableField> variableFields;
}
public class VariableField extends MessageField{
    public int id;
}

yaml:

name: field3
type: short
length: 2
comment:
variableFields:
  - !com.mylib.VariableField
    id: 1
    name: nestedField 1
    type: string
    length: -1
    comment:
---

The yaml documentation page describes how to deserialize a class by specifying the type when reading the class, which is what I do for my top level class:

YamlReader reader = new YamlReader(new FileReader("sample.yml"));
MessageField mf = reader.read(MessageField.class);

This correctly parses my fields for the top level class, but does not allow me to avoid the !com.mylib.VariableField identifier for my nested class. I’m trying to figure out if there is any way to change the Java code so that the yaml files are not required to know the class name.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-31T04:22:53+00:00Added an answer on May 31, 2026 at 4:22 am

    I believe what you are looking for is

    reader.getConfig().setPropertyElementType(MessageField.class, "variableFields", VariableField.class);
    

    which sets the default element type for collection-based fields. Similarly, the setPropertyDefaultType method can be used to specify the default type of a field itself.

    With default field/element types specified for a YamlReader, you should no longer need to include class names in the yaml file (though any type names which you do include will override these defaults). Also, if default types are defined for a YamlWriter, superfluous class names will not be written to the yaml file.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have thousands of HTML files to process using Groovy/Java and I need to
I have a string like this: La Torre Eiffel paragonata all&#8217;Everest What PHP function
this is what i have right now Drawing an RSS feed into the php,
I have a bunch of posts stored in text files formatted in yaml/textile (from
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I have a French site that I want to parse, but am running into
I'm parsing an RSS feed that has an &#8217; in it. SimpleXML turns this
I have this code: - (void)parser:(NSXMLParser *)parser foundCDATA:(NSData *)CDATABlock { NSString *someString = [[NSString
I have this code to decode numeric html entities to the UTF8 equivalent character.
I'm new to using the Perl treebuilder module for HTML parsing and can't figure

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.