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Home/ Questions/Q 6390113
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T03:29:12+00:00 2026-05-25T03:29:12+00:00

im very new at javascipt (im php developer) so im really confused trying to

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im very new at javascipt (im php developer) so im really confused trying to get this working.

In my web form i have 3 textfields (name, description and year) that i need to let the user add as many he needs, clicking on a web link, also, any new group of text fields need to have a new link on the side for removing it (remove me).

I tried some tutorial and some similar questions on stackoverflow but i dont get it well. If you can show me a code example just with this function i may understand the principle. Thanks for any help!

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  1. Editorial Team
    Editorial Team
    2026-05-25T03:29:12+00:00Added an answer on May 25, 2026 at 3:29 am

    this is the simplest thing that has come to my mind, you can use it as a starting point:

    HTML

    <div class='container'>
        Name<input type='text' name='name[]'>
        Year<input type='text' name='year[]'>
        Description<input type='text' name='description[]'>
    </div>
    <button id='add'>Add</button>
    <button id='remove'>Remove</button>
    

    jQuery

    function checkRemove() {
        if ($('div.container').length == 1) {
            $('#remove').hide();
        } else {
            $('#remove').show();
        }
    };
    $(document).ready(function() {
        checkRemove()
        $('#add').click(function() {
            $('div.container:last').after($('div.container:first').clone());
            checkRemove();
        });
        $('#remove').click(function() {
            $('div.container:last').remove();
            checkRemove();
        });
    });
    

    fiddle here: http://jsfiddle.net/Fc3ET/

    In this way you take advantage of the fact that in PHP you can post arrays: server side you just have to iterate on $_POST[‘name’] to access the various submissions

    EDIT – the following code is a different twist: you have a remove button for each group:

    $(document).ready(function() {
        var removeButton = "<button id='remove'>Remove</button>";
        $('#add').click(function() {
            $('div.container:last').after($('div.container:first').clone());
            $('div.container:last').append(removeButton);
    
        });
        $('#remove').live('click', function() {
            $(this).closest('div.container').remove();
        });
    });
    

    Fiddle http://jsfiddle.net/Fc3ET/2/

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