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Home/ Questions/Q 8871509
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T18:00:33+00:00 2026-06-14T18:00:33+00:00

I’m very new to nodejs and have a question. Trying to create a function

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I’m very new to nodejs and have a question.

Trying to create a function that will call the value of any field where I mention its ID from a table:

function getUserInfo (userID, dynamicField) {
    var query = connection.query('SELECT '+dynamicField+' from users WHERE userID = '+connection.escape(userID));
    query.on('result', function(row) {
        return(row.dynamicField);
    });
};
console.log(getUserInfo(8, userEmail)) //this should get me the userEmail value of the user with userID=8

However, I get “undefined”. If I use console.log rather than return, it logs the value but this has no use as a function to be used inside other functions to get a value.

I will be glad if I can get help for modifying the function.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-14T18:00:35+00:00Added an answer on June 14, 2026 at 6:00 pm

    This is a common mistake amongst async/nodejs beginners. You have essentially wrapped an async function inside a sync function which breaks down the nature of node’s event loop. The return expression needs to be replaced with a callback. See below:

    // Method
    function getUserInfo (userID, dynamicField, callback) {
        var query = connection.query('SELECT '+dynamicField+' from users WHERE userID = '+connection.escape(userID));
        query.on('result', function(row) {
            callback(null, row.dynamicField);
        });
    };
    
    // Implementation
    getUserInfo(8, userEmail, function(err, result){
        console.log(err || result);
    });
    

    By convention, in Nodejs we always pass an error object first in the callback. In this case since there is no error to capture, we pass null in its place.

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