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Editorial Team
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Asked: 2026-06-14T08:49:43+00:00

I’m very new to Web programming and am trying to write a simple application

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I’m very new to Web programming and am trying to write a simple application to collect data from an input form and pass it to a servlet via HTTPServletRequest. I know each servlet needs to be mapped to a particular URL inside web.xml. My web.xml looks as follows:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>InputFormTest</display-name>
  <welcome-file-list>
    <welcome-file>InputForm.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <description></description>
    <display-name>InputFormTest</display-name>
    <servlet-name>InputFormTest</servlet-name>
    <servlet-class>com.jsp.core.InputFormTest</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>InputFormTest</servlet-name>
    <url-pattern>/InputFormTest</url-pattern>
  </servlet-mapping>
</web-app>

InputForm.jsp shows correctly. I’ve added the InputFormTest servlet using Eclipse’s context menu, i.e. New -> Servlet, which has the following code:

package jsp.core;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class InputFormTest
 */
public class InputFormTest extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        response.setContentType("text/html");
        PrintWriter out = response.getWriter();
        out.println("<html>");
        out.println("<head>");
        out.println("<title>InputFormTest</title>");
        out.println("</head>");
        out.println("<body>");
        out.println("<h1>User inserted: " + request.getParameter("id") + "</h1>");
        out.println("</body>");
        out.println("</html>");
    }
}

I have two problems:

  1. Firstly, after running the application within Eclipse, I’m getting the following error

    HTTP Status 404 – /InputFormTest

    type Status report

    message /InputFormTest

    description The requested resource is not available.

    Apache Tomcat/6.0.36

  2. Secondly, changing <url-pattern>/InputFormTest</url-pattern> in web.xml doesn’t influence the above output, which is weird, because I’d assume message /InputFormTest should reflect the setting within web.xml

Any hints appreciated.

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1 Answer

  1. Editorial Team

    OK, I finally figured it out. As one could guess, the answer is trivial: Eclipse internal browser caches pages.

    This means, the page being shown in Eclipse internal browser after running the newly changed project using “Run as -> Run on server” is an old, cached page. It needs to be manually refreshed afterwards. Kind of weird behavior in case of a web-development project. Apart from that, everything works fine – case closed.

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