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Home/ Questions/Q 363621
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T13:21:36+00:00 2026-05-12T13:21:36+00:00

I’m well aware that in C++ int someValue = i++; array[i++] = otherValue; has

  • 0

I’m well aware that in C++

int someValue = i++;
array[i++] = otherValue;

has different effect compared to

int someValue = ++i;
array[++i] = otherValue;

but every once in a while I see statements with prefix increment in for-loops or just by their own:

for( int i = 0; i < count; ++i ) {
     //do stuff
}

or

for( int i = 0; i < count; ) {
    //do some stuff;
    if( condition ) {
        ++i;
    } else {
        i += 4;
    }
}

In the latter two cases the ++i looks like an attempt to produce smarty-looking code. Am I overseeing something? Is there a reason to use ++i instead of i++ in the latter two cases?

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  1. Editorial Team
    Editorial Team
    2026-05-12T13:21:36+00:00Added an answer on May 12, 2026 at 1:21 pm

    If we ignore force of habit, ‘++i’ is a simpler operation conceptually: It simply adds one to the value of i, and then uses it.

    i++ on the other hand, is “take the original value of i, store it as a temporary, add one to i, and then return the temporary”. It requires us to keep the old value around even after i has been updated.

    And as Konrad Rudolph showed, there can be performance costs to using i++ with user-defined types.

    So the question is, why not always just default to ++i?

    If you have no reason to use `i++´, why do it? Why would you default to the operation which is more complicated to reason about, and may be slower to execute?

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