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Home/ Questions/Q 7657485
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T13:02:35+00:00 2026-05-31T13:02:35+00:00

I’m wondering if the default implementation of Java’s Hashtable#hashCode() is broken when the Hashtable

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I’m wondering if the default implementation of Java’s Hashtable#hashCode() is broken when the Hashtable contains only entries with identical keys and values per pair.

See for example the following application:

public class HashtableHash {
    public static void main(final String[] args) {
        final Hashtable<String, String> ht = new Hashtable<String, String>();

        final int h1 = ht.hashCode();
        System.out.println(h1); // output is 0

        ht.put("Test", "Test");

        final int h2 = ht.hashCode();
        System.out.println(h2); // output is 0 ?!?

        // Hashtable#hashCode() uses this algorithm to calculate hash code
        // of every element:
        //
        // h += e.key.hashCode() ^ e.value.hashCode()
        //
        // The result of XOR on identical hash codes is always 0
        // (because all bits are equal)

        ht.put("Test2", "Hello world");

        final int h3 = ht.hashCode();
        System.out.println(h3); // output is some hash code
    }
}

The hash code for an empty Hashtable is 0. After an entry with the key "Test" and value "Test" has been added to the Hastable the hash code still is 0.

The problem is that in Hashtable’s hashCode() method the hash code of every entry is calculated and added to the hash code as follows

h += e.key.hashCode() ^ e.value.hashCode()

However XOR on identical hash codes (which is the case for identical Strings) is always 0. So entries with identical keys and values are not part of the Hashtable’s hash code.

This implementation is imho broken because the Hashtable actually has changed. It shouldn’t matter if key and value are identical.

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  1. Editorial Team
    Editorial Team
    2026-05-31T13:02:36+00:00Added an answer on May 31, 2026 at 1:02 pm

    From the documentation on hashCode;

    It is not required that if two objects are unequal according to the
    equals(java.lang.Object) method, then calling the hashCode method on
    each of the two objects must produce distinct integer results.
    However, the programmer should be aware that producing distinct
    integer results for unequal objects may improve the performance of
    hashtables.

    In other words, bad implementation – perhaps. Broken – not according to the spec.

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