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Home/ Questions/Q 6942277
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T12:59:39+00:00 2026-05-27T12:59:39+00:00

I’m wondering if there is a more efficient way to do this, from a

  • 0

I’m wondering if there is a more efficient way to do this, from a CPU time standpoint:

/*
* Returns a string in the form of "n days, x hours, y minutes"
* */

public static String getFormattedDateDifference(DateTime startDate, DateTime endDate) {
    Period p = new Period(startDate, endDate,
            PeriodType.standard().withSecondsRemoved().withMillisRemoved());
    return PeriodFormat.getDefault().print(p);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T12:59:40+00:00Added an answer on May 27, 2026 at 12:59 pm

    This, maybe?

    private static final Pattern PATTERN = Pattern.compile(", $");
    
    public static String getFormattedDateDifference(final DateTime startDate,
        final DateTime endDate)
    {
        // This variable will ultimately contain the number of days
        long days = endDate.getMillis() - startDate.getMillis();
    
        final long hours, minutes;
    
        days /= 60000; // Forget seconds and milliseconds
    
        minutes = days % 60;  days /= 60;
    
        hours = days % 24; days /= 24;
    
        final StringBuilder sb = new StringBuilder();
    
        if (days != 0) {
            sb.append(days).append(" day");
            if (days > 1)
                sb.append('s');
            sb.append(", ");
        }
        if (hours != 0) {
            sb.append(hours).append(" hour");
            if (hours > 1)
                sb.append('s');
            sb.append(", ");
        }
        if (minutes != 0) {
            sb.append(minutes).append(" minute");
            if (minutes > 1)
                sb.append('s');
            sb.append(", ");
        }
    
        return PATTERN.matcher(sb.toString()).replaceFirst("");
    }
    

    With this simple main(), it shows a more than double speedup:

    public static void main(final String... args)
    {
        final DateTime d = DateTime.now();
    
        final DateTime d2 = d.minus(Days.days(1)).minus(Minutes.minutes(3));
    
        long start, end;
    
        final int count = 5000;
        int i;
    
        start = System.currentTimeMillis();
        for (i = 0; i < count; i++)
            getFormattedDateDifference(d2, d); // <-- the original implementation
        end = System.currentTimeMillis();
    
        System.out.println(end - start);
    
        start = System.currentTimeMillis();
        for (i = 0; i < count; i++)
            getFormattedDateDifference2(d2, d); // <-- the implementation above
        end = System.currentTimeMillis();
    
        System.out.println(end - start);
    
        System.exit(0);
    }
    

    383 ms for the original function, 150 ms for mine.

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