Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7187361
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 28, 20262026-05-28T18:49:42+00:00 2026-05-28T18:49:42+00:00

I’m wondering why these two following conditions in SQL return different results First Condition

  • 0

I’m wondering why these two following conditions in SQL return different results

First Condition
I write query as following :

DECLARE @idUser VARCHAR(MAX)
SELECT @idUser = COALESCE(@idUser+', ' , '') + CAST(idUser as VARCHAR(MAX))
FROM webuser
WHERE username IN ('John', 'Tom')

And it returns the user id for each usernames, below is the output given

1020, 1021

Second Condition
I write another different query. The username is already set as a parameter, and this is actually what I need, the username is set as parameter, below is the query used :

DECLARE @username VARCHAR(MAX)
SET @username = '''John'', ''Tom'''
DECLARE @idUser VARCHAR(MAX)
SELECT @idUser = COALESCE(@idUser+', ' , '') + CAST(idUser as VARCHAR(MAX))
FROM webuser
WHERE username IN (@username)

And it returns NULL value as the result.

I’m expecting the two queries return same output, I’m thinking that it’s something about the quote in the @username, did I do it wrong or do you guys have any explanation and solution for this case ?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-28T18:49:43+00:00Added an answer on May 28, 2026 at 6:49 pm

    @username is a single string variable, not an array of strings. So your query where you replace the variable is looking for a single username in the table with the value 'John', 'Tom', not two separate values 'John' and 'Tom'… SQL Server doesn’t know what an array is, and can’t transform that string into multiple values for you.

    You will need to use dynamic SQL or split the values first.

    Dynamic SQL:

    DECLARE 
        @s VARCHAR(MAX),
        @username VARCHAR(MAX);
    
    SELECT 
        @s = '', 
        @username = '''John'', ''Tom''';
    
    DECLARE @sql NVARCHAR(MAX);
    SELECT @sql  = N'SELECT @s = @s + '',''
        + CONVERT(VARCHAR(MAX), idUser) 
      FROM dbo.webuser
      WHERE username IN (' + @username + ');';
    
    EXEC sp_executesql 
        @sql, 
        N'@s VARCHAR(MAX) OUTPUT', 
        @s = @s OUTPUT;
    
    PRINT STUFF(@s, 1, 1, '');
    

    Some ideas for splitting here: Passing a varchar full of comma delimited values to a SQL Server IN function

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

link Im having trouble converting the html entites into html characters, (&# 8217;) i
I'm using v2.0 of ClassTextile.php, with the following call: $testimonial_text = $textile->TextileRestricted($_POST['testimonial']); ... and
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
We're building an app, our first using Rails 3, and we're having to build
I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I ran into a problem. Wrote the following code snippet: teksti = teksti.Trim() teksti
I'm making a simple page using Google Maps API 3. My first. One marker
That's pretty much it. I'm using Nokogiri to scrape a web page what has
I have just tried to save a simple *.rtf file with some websites and
I want to count how many characters a certain string has in PHP, but

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.