Question

I’m working on a app that requires a DB and I’m getting some problems, the code seems good but its only printing 1 row when I have 2, I have tested when I have it with 5 and I still get 1.

What I’m wanting to do is make an array of all the item_id’s; I know I’m getting all fields at the moment but that was just for testing.

index.php:

<?php

mysql_connect('localhost', 'aaran', '*********');
mysql_select_db('aaran_aff_io');

$query = mysql_query("SELECT * FROM `items` WHERE `owner`='aaranmcguire'");
$results = mysql_fetch_array($query);

echo '<pre>';
print_r($results);

?>

DB:

DB Structure:

CREATE TABLE `items` (
  `id` int(11) unsigned NOT NULL AUTO_INCREMENT,
  `item_id` int(11) NOT NULL,
  `name` varchar(55) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
  `thumbnail` varchar(255) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
  `url` varchar(255) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
  `owner` varchar(55) COLLATE utf8_unicode_ci NOT NULL DEFAULT '',
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=5 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

Answer 1

mysql_fetch_array only returns one row at a time. If you want all the rows placed into an array, you can iterate over the result set:

$query = mysql_query("SELECT * FROM `items` WHERE `owner`='aaranmcguire'");
$rows = array();
while ($row = mysql_fetch_array($query)) {
    $rows[] = $row;
}

echo '<pre>';
print_r($rows);