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Home/ Questions/Q 7061143
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:26:17+00:00 2026-05-28T04:26:17+00:00

I’m working on a blog like application, my user module has_many posts and the

  • 0

I’m working on a blog like application,
my user module has_many posts and the posts module belongs_to user

I want to access both users/:id/posts and posts/

routes.rb is something like this:

resources :users do
  resources :posts
end

resources:posts

how can i know within the posts controller if its accessed directly (/posts) or through the nested route (/users/:id/posts) ?

for example, what should be the index method of the posts controller for doing the correct INDEX action for /users/:id/posts and for /posts

is there a better way for doing this ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:26:18+00:00Added an answer on May 28, 2026 at 4:26 am

    One solution could be to use a before filter on your controller, like:

    before_filter :load_user
      
    def load_user
      @user = User.find(params[:user_id]) if params[:user_id]
      @posts = @user ? @user.posts : Post.all
    end
    

    Then you have to rewrite your controller a bit to function properly.

    No refactoring needed on index action, @posts already loaded correctly, but you can do further filtering as you like

    def index
      @posts = @posts.where('updated_at < ?' Time.now)
    end
    

    Then update every member action: new, create, show, edit, update, destroy and use posts as a base like:

    def new
      @post = @posts.build
    end
    
    def create
      @post = @posts.build(params[:task])
    end
    
    def show
      @post = @posts.find(params[:id])
    end
    
    def edit
      @post = @posts.find(params[:id])
    end
    
    def update
      @post = @posts.find(params[:id])
    end
    
    def destroy
      @post = @posts.find(params[:id])
    end
    

    Of course you can add other before filters to remove duplicate code.

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