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Home/ Questions/Q 6057877
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T08:32:12+00:00 2026-05-23T08:32:12+00:00

I’m working on a CakePHP application. I’m trying to redirect the user to admin

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I’m working on a CakePHP application. I’m trying to redirect the user to admin URL based on his/her IP address and for that I’m using this code in app_controller.php

        if(env('REMOTE_ADDR')=='foo') {

        $this->redirect(array('action'=>'index', 'admin'=>1));
        echo $html->link(__('Logout', true), array('controller'=> 'users', 'action'=>'admin_index')); 
        }

I’m getting a redirect loop as soon the condition matches. 🙁

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  1. Editorial Team
    Editorial Team
    2026-05-23T08:32:13+00:00Added an answer on May 23, 2026 at 8:32 am

    This is because your app controller fires code before anything else. The code you’ve written essentially translates to

    1. Visit URL => AppController fires, sends you to /admin/controller/index/
    2. In /admin/controller/index/ AppController fires again and sends you to /admin/controller/index/
    3. As above

    Another thing, you seem to be echoing a link after you do a redirect, this doesn’t serve any purpose.

    What you probably want is something like this

    $url = 'Wherever you are redirecting to';
    if (env('REMOTE_ADDR') == 'foo' && $this->params['url']['url'] != $url) {
       $this->redirect($url);
    }
    

    Also, when you do $this->redirect(array('action'=>'index', 'admin'=>1)); you’re essentially redirecting to the index action of whichever URL you are in. Is this what you’re trying to do? If so, you’ll need to modify your check to something like

    $url = 'Wherever you are redirecting to';
    if (env('REMOTE_ADDR') == 'foo' && $this->params['action'] != 'index' && $this->params['admin'] != 1) {
       $this->redirect($url);
    }
    
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