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Home/ Questions/Q 3598508
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:15:03+00:00 2026-05-18T20:15:03+00:00

I’m working on a Chrome extension an I’ve hit a wall. function isInQueue(id) {

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I’m working on a Chrome extension an I’ve hit a wall.

function isInQueue(id) {
    chrome.extension.sendRequest({getQueueItems: 1}, function(response) {
        var items = response.items;
        if (items) {
            for (var i = 0; i < items.length; i++) {
                if ((items[i].id == id) == true) return true;
            }
            return false;
        } else { return false; }
    });
}

The request returns ‘items’ which is an array of objects. I am trying to see if another item outside of the queue already exists inside the queue. For example, there is an item on the outside with an id equal to ‘198677’. I know I already have an exact copy of that same item in my queue with the exact same id, ‘198677’, however, when I test the two for equality (items[i].id == id) == true, it returns false. I have checked the typeof both and they are both strings. I have tried using === and that hasn’t worked. I tried adding zero to each of them to turn them into integers and that made the function return true when it was actually true, however, when I tested for true if (isInQueue(id) == true) the conditional returned false.

This is all very confusing and frustrating for me. They’re both strings, why doesn’t it work?

Help is very much appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:15:04+00:00Added an answer on May 18, 2026 at 8:15 pm

    I figured it out:

    function isInQueue(id) {
        var result = false;
        var queue = localStorage["queue_rss"];
        if (queue != undefined) {
            var items = JSON.parse(queue).items;
            if (items) {
                for (var i = 0; i < items.length; i++) {
                    if ((items[i].id == id) == true) {
                      result = true;
                      break;
                    }
                }
            }
        }
        return result;
    }
    

    I should have done it that way in the first place.
    Thanks guys. 😀

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