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Home/ Questions/Q 7402353
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:43:22+00:00 2026-05-29T04:43:22+00:00

I’m working on a code I requested from a researching team. I’m trying to

  • 0

I’m working on a code I requested from a researching team. I’m trying to understand the code, however, they used malloc in a strange way. here;

in the header file;

 #define ERROR_OUTPUT stderr
 #define FAILIF(b) {   \
   if (b) {  \
       fprintf(ERROR_OUTPUT, "FAILIF triggered on line %d, file %s. Memory allocated: %lld\n",  \
       __LINE__, __FILE__, totalAllocatedMemory); exit(1); \
   } \
  }
 #define MALLOC(amount) \ 
   ( (amount > 0) ? totalAllocatedMemory += amount, malloc(amount) : NULL)

in the cpp file;

 double *memRatiosForNNStructs = NULL;
 double *listOfRadii = NULL;
 nRadii = 1;
 FAILIF(NULL == (memRatiosForNNStructs = (double*)MALLOC(nRadii * sizeof(double))));

From my understanding, the MALLOC that they defined means the following;

if(amount>0) // which is true; at least in this case
{
   totalAllocatedMemory = totalAllocatedMemory + amount; // sounds reasonable
   malloc(amount)  // What?? This will leak memory...
}
else
{
   NULL; // Do nothing? I guess that's fine
}

Is there something that I’m missing here? Or did they just make a (naive) mistake?

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  1. Editorial Team
    Editorial Team
    2026-05-29T04:43:23+00:00Added an answer on May 29, 2026 at 4:43 am

    The third code snippet you have is not equivalent. Notice the use of the comma operator:

    #define MALLOC(amount) \
        ( (amount > 0) ? totalAllocatedMemory += amount, malloc(amount) : NULL)  
                                                       ^
                                                      N.B.!
    

    The comma operator takes two arguments, evaluates and discards the first expression, then evaluates and returns the second expression.

    The ternary conditional operator used this way

    a = ((b)?(c:d))
    

    is equivalent to this

    if(b) {
        a = c;
    }
    else {
        a = d;
    }
    

    The comma operator used this way

    e = f, g;
    

    is equivalent to this

    f;
    e = g;
    

    So if you have

    a = ((b)?(f,g:d))
    

    then that is equivalent to

    if(b) {
        f;
        a = g;
    }
    else {
        a = d;
    }
    

    In the code provided in your original post, the MALLOC macro is to be used like this:

    memRatiosForNNStructs = (double*)MALLOC(nRadii * sizeof(double));
    

    which is equivalent to this:

       // First operand of ternary conditional
    if(nRadii * sizeof(double) > 0)
    {
        // Second  operand of ternary conditional
    
        // First expression of the comma operator
        totalAllocatedMemory += nRadii * sizeof(double));
        // Second expression of the comma operator
        memRatiosForNNStructs = (double*)malloc(nRadii * sizeof(double));
    }
    else
    {
        // Third operand of ternary conditional
        memRatiosForNNStructs = (double*)NULL;
    }
    

    Honestly though, this could be achieved as a function in C with no loss of generality:

    void* my_malloc(unsigned int amount)
    {
        if(amount > 0) {
            // I assume this is a global variable
            totalAllocatedMemory = totalAllocatedMemory + amount;
            return  malloc(amount);
        }
        else {
            return NULL;
        } 
    }
    
    memRatiosForNNStructs = (double*)my_malloc(nRadii * sizeof(double));
    

    So I’m not sure what’s the point of even implementing it as a hard-to-read macro.

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