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Home/ Questions/Q 7686369
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:27:51+00:00 2026-05-31T19:27:51+00:00

I’m working on a conference application where we want the sessions to be first

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I’m working on a conference application where we want the sessions to be first grouped by time and then by room location. I have successfully sorted by one or the other in my ExpandableListActivity, but have been unsuccessful with both the primary and secondary sort.

conference application that displays the sessions first grouped by time and then by room location
(source: coreylatislaw.com)

Set up

  • Custom content provider (extends ContentProvider)
  • Custom list adapter (extends BaseExpandableListAdapter)
  • Custom list activity (extends ExpandableListActivity)

Query

    Cursor cursor = context.getContentResolver()
                           .query(uri,
                                  ScheduleData.PROJECTION,
                                  null,
                                  null,
                                  ScheduleData.SORT_ORDER);

Sort order

    public static final String SORT_ORDER = TimeSlots.QUALIFIED_TIMESTART + " ASC"; // timeslots.timestart

Failed primary & secondary sort orders

    public static final String SORT_ORDER = TimeSlots.QUALIFIED_TIMESTART + " ASC, " + Locations.QUALIFIED_NAME + " ASC"; // timeslots.timestart ASC, locations.name ASC
    public static final String SORT_ORDER = TimeSlots.QUALIFIED_TIMESTART + ", " + Locations.QUALIFIED_NAME + " ASC";     // timeslots.timestart, locations.name ASC

The second clause seems to have no affect on the ordering. Is this a limitation of the ExpandableListActivity? Should I specify multiple sort order items differently?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T19:27:52+00:00Added an answer on May 31, 2026 at 7:27 pm

    Turns out that there was a comparator in the class that was overriding the sort order specified in the ORDERBY clause. When using the ORDERBY clauses above with out the comparator, I got the desired sorting. You can do it either way, but I’m killing the extra code and choosing the ORDERBY clause.

    The comparator path:

    // Sort children
    Collections.sort(group.children, CHILD_COMPARATOR);
    
    // Specify sort by location
    static final Comparator<Child> CHILD_COMPARATOR = new Comparator<Child>()
    {
        @Override
        public int compare (Child child1, Child child2)
        {
            return child1.location.toLowerCase().compareTo(child2.location.toLowerCase());
        }
    };
    
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