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Home/ Questions/Q 6929563
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:20:02+00:00 2026-05-27T11:20:02+00:00

I’m working on a cortex-m3 board with a bare-metal toolchain without libc. I implemented

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I’m working on a cortex-m3 board with a bare-metal toolchain without libc.

I implemented memcpy which copies data byte-to-byte but it’s too slow. In GCC manual, it says it provides __builtin_memcpy and I decided to use it. So here is the implementation with __builtin_memcpy.

#include <stddef.h>

void *memcpy(void *dest, const void *src, size_t n)
{
    return __builtin_memcpy(dest,src,n);
}

When I compile this code, it becomes a recursive function which never ends.

$ arm-none-eabi-gcc -march=armv7-m -mcpu=cortex-m3 -mtune=cortex-m3 \
  -O2 -ffreestanding -c memcpy.c -o memcpy.o
$ arm-none-eabi-objdump -d memcpy.o

memcpy.o:     file format elf32-littlearm


Disassembly of section .text:

00000000 <memcpy>:
   0:   f7ff bffe       b.w     0 <memcpy>

Am I doing wrong? How can I use the compiler-generated memcpy version?

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:20:03+00:00Added an answer on May 27, 2026 at 11:20 am

    Builtin functions are not supposed to be used to implement itself 🙂

    Builtin functions are supposed to be used in application code – then the compiler may or may not generate some special insn sequence or a call to the underlying real function

    Compare:

    int a [10], b [20];
    
    void
    foo ()
    {
      __builtin_memcpy (a, b, 10 * sizeof (int));
    }
    

    This results in:

    foo:
        stmfd   sp!, {r4, r5}
        ldr     r4, .L2
        ldr     r5, .L2+4
        ldmia   r4!, {r0, r1, r2, r3}
        mov     ip, r5
        stmia   ip!, {r0, r1, r2, r3}
        ldmia   r4!, {r0, r1, r2, r3}
        stmia   ip!, {r0, r1, r2, r3}
        ldmia   r4, {r0, r1}
        stmia   ip, {r0, r1}
        ldmfd   sp!, {r4, r5}
        bx      lr
    

    But:

    void
    bar (int n)
    {
      __builtin_memcpy (a, b, n * sizeof (int));
    }
    

    results in a call to the memcpy function:

    bar:
        mov     r2, r0, asl #2
        stmfd   sp!, {r3, lr}
        ldr     r1, .L5
        ldr     r0, .L5+4
        bl      memcpy
        ldmfd   sp!, {r3, lr}
        bx      lr
    
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