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Home/ Questions/Q 6252827
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:52:34+00:00 2026-05-24T13:52:34+00:00

I’m working on a dynamic validation system. For some reason, shift() on the args

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I’m working on a dynamic validation system. For some reason, shift() on the args array mainfunc passes to validateNumber does not act properly. Here’s the code with output in comments next to alert boxes:

function mainfunc (func){
    //this calls the function validateNumber and passes args to it.
    this[func].apply(this, Array.prototype.slice.call(arguments, 1));
}

function validateNumber(args) {
    alert(args); //this functions normally. for example, displays fish,3,5
    var text = args.shift; //would expect this to return 'fish', right?
    alert(text); //instead of 'fish' alerts 'function shift() { [native code] }'. This is the problem.
    var minimum = args.shift;
    var maximum = args.shift;
    return text;
}

validationArgs = classList[i].split('-');
    functionName = validationArgs.shift();
    validationArgs.unshift($(this).val());
    mainfunc(functionName, validationArgs); //calls mainfunc which calls the function

I’m stumped as to why this behaves this way. Note: I cribbed mainfunc from this StackOverflow answer: Calling dynamic function with dynamic parameters in Javascript

Edit: Oh, my goodness. I am an idiot. I even use shift() correctly in the title of the question! Thanks all.

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:52:35+00:00Added an answer on May 24, 2026 at 1:52 pm

    This:

    var text = args.shift;
    

    is not a method call, you want:

    var text = args.shift();
    

    All your original does is assigns the shift method from args to text, hence your:

    function shift() { [native code] }
    

    output in your alert. Doing a args.shift won’t have any effect on args so these two:

    var minimum = args.shift;
    var maximum = args.shift;
    

    just give you two more reference’s to args.shift without changing args at all.

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