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Home/ Questions/Q 6740555
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T11:37:11+00:00 2026-05-26T11:37:11+00:00

I’m working on a homework problem for class. Where you have to calculate the

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I’m working on a homework problem for class. Where you have to calculate the distance between two points. The code is basically done, but I have one question. When I enter q to end the loop. I get a message back.

Exception in thread “main” java.lang.NumberFormatException: For input string: “q”

at.sun.misc.FloatingDecimal.readJavaFormatString(Unkown Source)

at java.lang.Double.parseDouble(Unkown Source)

atDistance.main(Distance.java:11)

import java.util.Scanner;
public class Distance {
public static void main(String[] args){
    Scanner input = new Scanner(System.in);
    while (true){
        System.out.print("Enter coordinate for x1: ");
        String x1String = input.next();
        if (x1String == "q")
            break;
            double x1 = Double.parseDouble(x1String);

        System.out.print("Enter coordinate for y1: ");
        String y1String = input.next();
        if (y1String == "q")
            break;
            double y1 = Double.parseDouble(y1String);

        System.out.print("Enter coordinate for x2: ");
        String x2String = input.next();
        if (x2String == "q")
            break;
            double x2 = Double.parseDouble(x2String);

        System.out.print("Enter coordinate for y2: ");
        String y2String = input.next();
        if (y2String == "q")
            break;
            double y2 = Double.parseDouble(y2String);

        double distance = (Math.pow(x2 - x1,2)) + (Math.pow(y2 - y1,2));
        distance = Math.sqrt(distance);
        System.out.printf("The distance is %5.2f",distance);
        System.out.println("");
    }
}//main
}//Distance

That is the code I have written. Any help is appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-26T11:37:11+00:00Added an answer on May 26, 2026 at 11:37 am

    You don’t do a string compare with ==. The “==” comparison checks to see if they are the exact same objects, not if the strings contain the same characters. Try x1String.equals("q") instead.

    What’s happening now is that the “==” will say “these aren’t the same object” and then it will attempt to parse the “q” as a double in the next line, which is throwing the exception.

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