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Home/ Questions/Q 8786225
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T21:33:53+00:00 2026-06-13T21:33:53+00:00

I’m working on a JavaScript project, and was just wondering why an object instance

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I’m working on a JavaScript project, and was just wondering why an object instance doesn’t inherit the defineProperty() and other methods, rather than having to call the superclass (superobject?) Object method.

I’ve looked at the MDN docs, and there are in fact “non-standard” property methods.

But those are deprecated. Why would the move be to the Object methods?

It seems to me that something like instance.defineProperty(...) is better than Object.defineProperty(instance, ...). I would say the same about some of the other Object methods as well.

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  1. Editorial Team
    Editorial Team
    2026-06-13T21:33:54+00:00Added an answer on June 13, 2026 at 9:33 pm

    It’s to avoid collisions – in general, issues with objects that do not have the property with the value that you expect.
    Objects in JS are often used as key-value-maps, and the keys can be arbitrary strings – for example __defineGetter__, hasOwnProperty or something less special. Now when you want to invoke such a function on an unknown object – like hasOwnProperty is often used in generic enumeration functions, where any JSON might be passed in – you can never be sure whether you got a overwritten property (that might not even be a function) or the original which you want, or whether the object inherits the property at all. To avoid this issue (or also this IE bug), you’d have to use Object.prototype.hasOwnProperty.call – that is ugly.

    So, namespacing all those functions on Object is only useful, it’s a cleaner API that separates the reflection methods from the object’s application interface. This also helps optimisation (simplifying static analysis) and makes it easier to restrict access to the reflection API in sandboxes – at least that was the design idea.

    You might be happy to have a defineProperty around in the prototype, but you can only use it safely when working with known objects. If you still want it (as you know when to use and when not), you could use

    Object.defineProperty(Object.prototype, "defineProperty", {
        writable: true,
        enumberable: false,
        value: function(prop, descr) {
            return Object.defineProperty(this, prop, descr); 
        }
    });
    
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