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Home/ Questions/Q 781023
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:10:03+00:00 2026-05-14T20:10:03+00:00

I’m working on a program that’s supposed to represent a graph. My issue is

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I’m working on a program that’s supposed to represent a graph. My issue is in my printAdjacencyList function. Basically, I have a Graph ADT that has a member variable “nodes”, which is a map of the nodes of that graph. Each Node has a set of Edge* to the edges it is connected to. I’m trying to iterate across each node in the graph and each edge of a node.

void MyGraph::printAdjacencyList() {
std::map<std::string, MyNode*>::iterator mit;
std::set<MyEdge*>::iterator sit;

for (mit = nodes.begin(); mit != nodes.end(); mit++ ) {
    std::cout << mit->first << ": {";
    const std::set<MyEdge*> edges = mit->second->getEdges();
    for (sit = edges.begin(); sit != edges.end(); sit++) {
        std::pair<MyNode*, MyNode*> edgeNodes = *sit->getEndpoints();
    }
}
std::cout << " }" << std::endl;
}

getEdges is declared as:

const std::set<MyEdge*>& getEdges() { return edges; };

and get Endpoints is declared as:

const std::pair<MyNode*, MyNode*>& getEndpoints() { return nodes; };

The compiler error I’m getting is:

MyGraph.cpp:63: error: request for member `getEndpoints' in 
`*(&sit)->std::_Rb_tree_const_iterator<_Tp>::operator->
[with _Tp = MyEdge*]()', which is of non-class type `MyEdge* const'

MyGraph.cpp:63: warning: unused variable 'edgeNodes'

I have figured out that this probably means I’m misusing const somewhere, but I can’t figure out where for the life of me. Any information would be appreciated. Thanks!

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:10:04+00:00Added an answer on May 14, 2026 at 8:10 pm

    Try changing sit to a const_iterator. Change mit to a const_iterator too while you’re at it. Also, getEdges() and getEndpoints() should be const functions. Lastly, because operator->() has a higher precedence than the unary operator*(), you probably want to say edgeNodes = (*sit)->getEndPoints() inside the inner-loop.

    Not as much of a problem but you should consider having the iterator instances as local to the loops.

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