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Home/ Questions/Q 498649
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T05:54:18+00:00 2026-05-13T05:54:18+00:00

I’m working on a programming language that uses C++ as it’s target language for

  • 0

I’m working on a programming language that uses C++ as it’s target language for now. I’m hitting an exceptionally strange backtrace.

#1  0x08048d09 in factorial (n=0x8052160) at ir.cpp:35
35      shore::builtin__int * __return = NULL;
(gdb) bt
#0  shore::builtin__int::__mul__ (this=0x8052160, other=0x8052288) at /home/alex/projects/shore/shore/runtime/int.h:36
#1  0x08048d09 in factorial (n=0x8052160) at ir.cpp:35
#2  0x08048cfa in factorial (n=0x80520b8) at ir.cpp:35
#3  0x08048cfa in factorial (n=0x8052018) at ir.cpp:35
#4  0x08048d6f in main () at ir.cpp:43

Specifically it appears that declaring the type of return is somehow triggering the __mul method on builtin__int to be called, and I have no idea why. builtin__int looks like:

#ifndef _SHORE_INT_H
#define _SHORE_INT_H

#include "gc.h"


namespace shore {
    class builtin__int : public shore::Object {
        public:
            // Some day this will be arbitrary percision, but not today.
            long long value;

            static builtin__int* new_instance(long long value_) {
                builtin__int* val = new builtin__int(value_);
                shore::GC::register_object(val);
                return val;
            }

            builtin__int(long long value_) {
                this->value = value_;
            }

            builtin__bool* __eq__(builtin__int* other) {
                return builtin__bool::new_instance(this->value == other->value);
            }

            builtin__int* __add__(builtin__int* other) {
                return builtin__int::new_instance(this->value + other->value);
            }

            builtin__int* __sub__(builtin__int* other) {
                return builtin__int::new_instance(this->value - other->value);
            }

            builtin__int* __mul__(builtin__int* other) {
                return builtin__int::new_instance(this->value * other->value);
            }
    };
}
#endif

Any ideas as to what on earth is compelling C++ to call the mul method?

EDIT: Added the source of ir.cpp

#include "builtins.h"
#include "frame.h"
#include "object.h"
#include "state.h"
std::vector < shore::Frame * >shore::State::frames;
shore::GCSet shore::GC::allocated_objects;
class
    factorial__frame:
    public
    shore::Frame {
  public:
    shore::builtin__int *
    n;
    shore::GCSet
    __get_sub_objects() {
    shore::GCSet s;
    s.
    insert(this->n);
    return
        s;
}};
class
    main__frame:
    public
    shore::Frame {
  public:
    shore::GCSet
    __get_sub_objects() {
    shore::GCSet s;
    return
        s;
}};
shore::builtin__int * factorial(shore::builtin__int * n)
{
    shore::builtin__int * __return = NULL;
    factorial__frame frame;
    shore::State::frames.push_back(&frame);
    frame.n = NULL;
    frame.n = n;
    if (((frame.n)->__eq__(shore::builtin__int::new_instance(0)))->value) {
    __return = shore::builtin__int::new_instance(1);
    shore::GC::collect();
    shore::State::frames.pop_back();
    return __return;
    }
    __return =
    (frame.n)->
    __mul__(factorial
        ((frame.n)->
         __sub__(shore::builtin__int::new_instance(1))));
    shore::GC::collect();
    shore::State::frames.pop_back();
    return __return;
}
int
main()
{
    main__frame     frame;
    shore::State::frames.push_back(&frame);
    builtin__print(factorial(shore::builtin__int::new_instance(3)));
    shore::State::frames.pop_back();
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T05:54:18+00:00Added an answer on May 13, 2026 at 5:54 am

    A bit of a guess: the initialization in the line shore::builtin__int * __return = NULL; does nothing, since it’s always overwritten. The compiler would be perfectly entitled to (a) reorder it down to where __return is assigned, by the statement that does call __mul__ and then (b) remove the code entirely. But maybe it’s left the source line in the debugging info, and either the linker or gdb has ended up thinking the call instruction belongs to the wrong one of the several source lines in the vicinity.

    Never trust source debugging unless you can see the disassembly too. Compiled languages – bah, humbug. And so forth.

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