Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 944831
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T22:39:31+00:00 2026-05-15T22:39:31+00:00

I’m working on a script that generate some Excel documents and I need to

  • 0

I’m working on a script that generate some Excel documents and I need to convert a number into its column name equivalent. For example:

1 => A
2 => B
27 => AA
28 => AB
14558 => UMX

I have already written an algorithm to do so, but I’d like to know whether are simpler or faster ways to do it:

function numberToColumnName($number){
    $abc = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    $abc_len = strlen($abc);

    $result_len = 1; // how much characters the column's name will have
    $pow = 0;
    while( ( $pow += pow($abc_len, $result_len) ) < $number ){
        $result_len++;
    }

    $result = "";
    $next = false;
    // add each character to the result...
    for($i = 1; $i<=$result_len; $i++){
        $index = ($number % $abc_len) - 1; // calculate the module

        // sometimes the index should be decreased by 1
        if( $next || $next = false ){
            $index--;
        }

        // this is the point that will be calculated in the next iteration
        $number = floor($number / strlen($abc));

        // if the index is negative, convert it to positive
        if( $next = ($index < 0) ) {
            $index = $abc_len + $index;
        }

        $result = $abc[$index].$result; // concatenate the letter
    }
    return $result;
}

Do you know a better way to do it? Maybe something to keep it simpler? or a performance improvement?

Edit

ircmaxell’s implementation works pretty fine. But, I’m going to add this nice short one:

function num2alpha($n)
{
    for($r = ""; $n >= 0; $n = intval($n / 26) - 1)
        $r = chr($n%26 + 0x41) . $r;
    return $r;
}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T22:39:31+00:00Added an answer on May 15, 2026 at 10:39 pm

    Here’s a nice simple recursive function (Based on zero indexed numbers, meaning 0 == A, 1 == B, etc)…

    function getNameFromNumber($num) {
        $numeric = $num % 26;
        $letter = chr(65 + $numeric);
        $num2 = intval($num / 26);
        if ($num2 > 0) {
            return getNameFromNumber($num2 - 1) . $letter;
        } else {
            return $letter;
        }
    }
    

    And if you want it one indexed (1 == A, etc):

    function getNameFromNumber($num) {
        $numeric = ($num - 1) % 26;
        $letter = chr(65 + $numeric);
        $num2 = intval(($num - 1) / 26);
        if ($num2 > 0) {
            return getNameFromNumber($num2) . $letter;
        } else {
            return $letter;
        }
    }
    

    Tested with numbers from 0 to 10000…

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 472k
  • Answers 472k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer for (UIWindow *keyboardWindow in [[UIApplication sharedApplication] windows]) for (UIView *keyboard… May 16, 2026 at 3:31 am
  • Editorial Team
    Editorial Team added an answer http://docs.jquery.com/Getjson paragraph 3 : "Note that the site you're trying… May 16, 2026 at 3:31 am
  • Editorial Team
    Editorial Team added an answer You can't follow the cursor with a DIV, but you… May 16, 2026 at 3:31 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.