Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 715239
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 14, 20262026-05-14T05:09:53+00:00 2026-05-14T05:09:53+00:00

I’m working on an application so i have write an dll which contain a

  • 0

I’m working on an application so i have write an dll which contain a form with some additional work and methods. so in the beginning of my program the thread launch this form (from my dll) to get some informations and then hide it and initialize some components and the application form and then show it. when the thread come the line where it define new instance of the exported form

"MyForm inputform = new MyForm();"

it throw an Exception called “Top-level control cannot be added to a control.” so i don’t know what to do ?!!. i tried to take the code of the form from the dll source code and put it in the main program and it works…. .but still i want to know what happen and what impede my application from run that form from my dll.
thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-14T05:09:54+00:00Added an answer on May 14, 2026 at 5:09 am

    The line that raises the error is possibly not the line you show above, but likely one of the lines that follows it. I.e., if you have something like the following:

    currentControl.Controls.Add(inputForm);
    

    it will not work and raise the error you mention.

    Instead, use inputForm.Show(ownerForm) to show the form when you want it and you should be fine. A form (a top level control) cannot be added to a normal control, like a panel, a textbox or a picturebox.

    Note: if the line in your post does raise the error, then inside the form initialization code lies a piece of code that raises the error, check there

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.