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Home/ Questions/Q 7901293
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T09:11:01+00:00 2026-06-03T09:11:01+00:00

I’m working on an application which renders out images side by side. When hovering

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I’m working on an application which renders out images side by side. When hovering an image a hidden class is revealed showing information of the image.

I also have a sort function so that one can sort the images by points (highest first, descending) instead of the default sort (date). Both hovering and sorting works fine, except for one thing.

When the images is sorted by points and rendered out again, hovering the images doesn’t work. I have looked at the generated code and it looks the same, but regardless that it doesn’t work.

I would really appreciate som help here, thanks!

<div id="images">
    <div class="image">
        <div class="post">
            // other code here
            <div class="postDesc">
                // other code here
                <p class="postDescContent">Points: 10</p>
            </div
        </div>
    </div>
    <div class="image">
        <div class="post">
            // other code here
            <div class="postDesc">
                // other code here
                <p class="postDescContent">Points: 20</p>
            </div
        </div>
    </div>
    // and so one...
</div>

sorting function:

sortByPoints: function() {
    var contents = $('div#images div[class^="image"]');

    contents.sort(function(a, b) {

        var p1= parseInt($('p.postDescContent', $(a)).text().replace('Points:','').trim()),
            p2 = parseInt($('p.postDescContent', $(b)).text().replace('Points:','').trim());
           return p1 < p2;

    });

    var images = $('#images');

    images.empty();
    images.append(contents);
}

hover function:

$('.image').hover(function () {
    $(this).find('.postDesc').toggle();
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T09:11:02+00:00Added an answer on June 3, 2026 at 9:11 am

    The .empty() method clears all element data. You shouldn’t need to empty it at all. Just do the .append().

    var images = $('#images');
    
    //images.empty();  // remove this
    
    images.append(contents);
    

    This should be sufficient to show the reordered elements without losing any handler data.

    live demo: http://jsfiddle.net/mgF3L/

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