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Home/ Questions/Q 3347848
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:28:15+00:00 2026-05-18T01:28:15+00:00

I’m working on an assignment for uni where I have to create a Breakout

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I’m working on an assignment for uni where I have to create a Breakout game in Visual Studio 2010 using C# Win Forms. At the moment, I am concentrating on there being only one brick to be destroyed so I have the mechanics down before expanding on it.

To clarify about my current program: I am using a picture box as a Graphics object and a timer to create the animation effect. The ball can skip, at each frame, between 1 and 10 pixels — this is part of creating a random starting vector for the ball.

This works fine until it comes to checking if the ball has ‘hit’ the brick I have drawn. What I have is an if statement that checks if the ball is at any of the coordinates on the picture box that corresponds to the outline of the brick. I know that the logic is fine because it works some of the time. However, because of the variation in the ‘jumping’ of the ball’s position, I need to add a buffer area of +/- 5 pixels to my if statement.

This is where the problem arises, because my if statement (two, really) is really complicated as it is:

// Checks if ball hits left side or top of brick
if (((x >= brickX) && (x <= (brickX + 50)) && (y == brickY)) ||
    ((y >= brickY) && (y <= (brickY + 20)) && (x == brickX)))
{
    brickHit = true;
}
// Check if ball hits right side or bottom of brick
else if ((((x >= brickX) && (x <= brickX + 50)) && (y == (brickY + 20))) ||
    (((y >= brickY) && (y <= brickY + 20)) && (x == brickX + 50)))
{
    brickHit = true;
}

For clarification: x and y are the coordinates of the ball and brickX and brickY are the coordinates of the top-left corner of the rectangle brick (which is 50 pixels wide, 10 pixels high).

Is there any way to simplify the above if statements? If I can make them simpler, I know it’ll be much easier to add in the ‘buffer’ (which only needs to be 5 pixels either side of the brick’s outline’ to allow for the ball’s change in position).

If further clarification is needed, please ask — I’m writing this question at 5:12am so I know I might be a little unclear.

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  1. Editorial Team
    Editorial Team
    2026-05-18T01:28:15+00:00Added an answer on May 18, 2026 at 1:28 am
    brickHit = new Rectangle(brickX,brickY,50,20).Contains(x,y);
    

    Adding a buffer:

    int buffer = 5;
    brickHit = new Rectangle(brickX,brickY,50,20).Inflate(buffer,buffer).Contains(x,y);
    

    The Rectagle class can come in handy sometimes.

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