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Home/ Questions/Q 8772429
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T18:01:44+00:00 2026-06-13T18:01:44+00:00

I’m working on another developers old code and there are tons of Notice: Undefined

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I’m working on another developers old code and there are tons of Notice: Undefined index errors when data is being set using the += operator. Essentially the index is not set yet in the array so the error is generated.

Example:

$myArray = array();
$myValue = 1;
for ($i = 1; $i <= 10; $i++) 
{
    $myArray['test'] += 1;
}

Will generate an error on the first run since the test index is not set yet.

I know I can remove this error with the following code:

$myArray = array();
$myValue = 1;
for ($i = 1; $i <= 10; $i++) 
{
    if ( ! isset($myArray['test']) )
    {
        $myArray['test'] = $myValue;
    } 
    else 
    {
        $myArray['test'] += $myValue;
    }
}

However, there are around 50 of things like this to change. Is it worth writing all these isset statements or is there a better way I am not aware of?

EDIT: I should note that the array indexes aren’t always the same and sometimes aren’t set so I can’t preset the index in this circumstance to avoid the error.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T18:01:46+00:00Added an answer on June 13, 2026 at 6:01 pm

    This is a bit shorter, but perhaps still a bit complicated if you have many edits.

    $myArray = array();
    $myValue = 1;
    for ($i = 1; $i <= 10; $i++) 
    {
        isset($myArray['test']) ? $myArray['test'] += $myValue : $myArray['test'] = $myValue;
    
    }
    

    You could also write a global function (not tested)..

    $myArray = array();   
    $myValue = 1;
    for ($i = 1; $i <= 10; $i++) 
    {
        increment($myArray['test'], $myValue);
    }
    
    function increment(&$var, $inc){
        $var = isset($var) ? $var += $inc : $var = $inc
    }
    
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