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Home/ Questions/Q 6706951
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T07:34:51+00:00 2026-05-26T07:34:51+00:00

I’m working on converting a neural network simulator from Perl to C. I have

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I’m working on converting a neural network simulator from Perl to C. I have it working, but I’m not happy with part of my code. I’ve defined a struct network (typedefed to NETWORK) which contains a pointer to an array of doubles and a pointer to an array of pointers to NEURONs, which is another struct. Here is how they are defined:

typedef struct neuron {
    double *inputweights;
    double *neuronweights;
    double value;
} NEURON; 

typedef struct network {
    NEURON **neurons;
    double *outputs;
} NETWORK;

Initially, I tried to initialize these like this:

NEURON* myvariable;

But of course that didn’t work because no memory was actually assigned. I know that I can initialize it like this:

NEURON myvariable;
NEURON* ptr = &myvariable;

But when I tried to do that into a loop, and stored the pointers in an array, it seemed like the previous pointers were lost or reset each iteration, and I was getting all sorts of errors. I was doing something like this:

NETWORK mynetwork;
for (i = 0; i < NEURON_COUNT; i++) {
    NEURON myneuron;
    reset_neuron(&myneuron); // Basically a zero fill of the arrays
    mynetwork->neurons[i]=&myneuron;
    myneuron->inputweights[0] = 1; // Sets the current neuron, first input
    printf("First neuron, first input is %f\n", mynetwork->neurons[0]->inputweights[0]);
    // The printf gives 1 on the first iteration, and 0 on every following iteration.
}

This gives me the impression that myneuron is always the /same/ memory location, even though I’m still keeping a pointer to the last one, so I keep resetting the same place. Of course I can also use malloc to force each neuron to be different:

NEURON* myvariable = malloc(sizeof(NEURON));

And that works, but that seems a bit like a kludge. Should I be bothering to use pointers to my structs at all? Is there a way to initialize a struct pointer without resorting to the low-level malloc and sizeof?

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:34:52+00:00Added an answer on May 26, 2026 at 7:34 am

    That’s exactly what malloc is for. When you need a varying number of objects of a particular type and need to control where they are allocated, you use malloc. Why does it seem like a kludge?

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