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Home/ Questions/Q 4621644
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:43:51+00:00 2026-05-22T02:43:51+00:00

I’m working on extending a legacy script system using groovy. The source scripts are

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I’m working on extending a legacy script system using groovy. The source scripts are “java-like”, so it mostly parses as a groovy script with a little pre-processing.

I’m using invokeMethod() and missingMethod() to pass-through the legacy code, enabling me to use closures and other groovy features to enhance the scripts. However, the original script uses strings of the type “$foo” to refer to variables. When a legacy method is caught by missingMethod(), I need it to not evaluate this string as a GString, but simply outputting it verbatim. Is this possible in any way?

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:43:52+00:00Added an answer on May 22, 2026 at 2:43 am

    there are two way to escape the $foo:

    1. escape the ‘$’ as ‘\$’
    2. use ‘ instead of ” as string delimiter

    example:

     def test = "bad"
     def s0 = "$test"
     def s1 = "\$test"
     assert s1 != s0
     def s2 = '$test'
     assert s2 == s1
     println s0
     println s1
     println s2
    

    So I guess you have to use your preprocessor in order to escape your strings

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