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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:23:01+00:00 2026-05-25T17:23:01+00:00

i’m working on image processing, and i’m writing a parallel algorithm that iterates over

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i’m working on image processing, and i’m writing a parallel algorithm that iterates over all the pixels in an image, and changes the surrounding pixels based on it’s value. In this algorithm, minor non-deterministic is acceptable, but i’d rather minimize it by only querying distant pixels simultaneously. Could someone give me an algorithm that bijectively maps the integers below n to the integers below n, in a fast and simple manner, such that two integers that are close to each other before mapping are likely to be far apart after application.

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:23:02+00:00Added an answer on May 25, 2026 at 5:23 pm

    Considering the pixels to be a one dimentional array you could use a hash function j = i*p % n where n is the zero based index of the last pixel and p is a prime number chosen to place the pixel far enough away at each step. % is the remainder operator in C, mathematically I’d write j(i) = i p (mod n).

    So if you want to jump at least 10 rows at each iteration, choose p > 10 * w where w is the screen width. You’ll want to have a lookup table for p as a function of n and w of course.

    Note that j hits every pixel as i goes from 0 to n.

    CORRECTION: Use (mod (n + 1)), not (mod n). The last index is n, which cannot be reached using mod n since n (mod n) == 0.

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