Question

im working on php page where for call contend in same page i’ve added

<?php if (isset($cpID)) {   echo ' '; }

i’ve added in the two ” some code that work nice, but have small troubles with this code:

onClick="location.href='waiting.php?picID='.$cpID.''"

it’s give me syntax error and i not know how place it in the PHP if set, please can help me? Thanks Stew

COMPLETE CODE:

<?php
if (isset($cpID)) {
    echo '</p><button class="btn btn-large btn-block btn-success" onClick="location.href='waiting.php?picID='.$cpID.''"  type="button">Click here to upload this Cover to your Facebook Profile</button></p>';
}
?>

Answer 1

Problem:

echo '
</p><button class="btn btn-large btn-block btn-success" onClick="location.href='waiting.php?picID='.$cpID.''"  type="button">Click here to upload this Cover to your Facebook Profile</button></p>
';
}

The problem is that your single quote for the echo is being closed by the one next to location.href=' You need to escape your single quotes.

---

Solution:

echo '
</p><button class="btn btn-large btn-block btn-success" onClick="location.href=\'waiting.php?picID='.$cpID.'\'"  type="button">Click here to upload this Cover to your Facebook Profile</button></p>
';

Please notice, I have escaped the single quotes with \'