Question

I’m working on python 3.2.2.
Breaking my head more than 3 hours to sort a dictionary by it’s keys.
I managed to make it a sorted list with 2 argument members, but can not make it a sorted dictionary in the end.

This is what I’ve figured:

myDic={10: 'b', 3:'a', 5:'c'}
sorted_list=sorted(myDic.items(), key=lambda x: x[0])

But no matter what I can not make a dictionary out of this sorted list. How do I do that? Thanks!

Answer 1

dict does not keep its elements’ order. What you need is an OrderedDict: http://docs.python.org/library/collections.html#collections.OrderedDict

edit

Usage example:

>>> from collections import OrderedDict
>>> a = {'foo': 1, 'bar': 2}
>>> a
{'foo': 1, 'bar': 2}
>>> b = OrderedDict(sorted(a.items()))
>>> b
OrderedDict([('bar', 2), ('foo', 1)])
>>> b['foo']
1
>>> b['bar']
2