Question

I’m working on simple queries to learn MySQL, in my example database, I keep track of Stores which sells electronic devices, I have a table Sells(Store, Item, Price).

And example data is,

'Best Buy', 'Galaxy S', 1000 
'Buy More', 'Macbook Air', 2000 
'Best Buy', 'Microsoft Mouse', 20 
'Best Buy', 'Macbook Pro Cover', 40 
'Buy More', 'Asus Zenbook', 2000

And so on..

I tried the following sql statement, but it says:

Error Code: 1111. Invalid use of group function 0.000 sec

SELECT store
FROM sells
WHERE SUM(price) <
        (SELECT SUM(price) AS total
        FROM sells
        GROUP BY store
        ORDER BY total DESC
        LIMIT 1) 
GROUP BY store
ORDER BY SUM(price) DESC

I would be appreciate if you can help me

Thanks

Answer 1

This will just plain show the second most expensive store;

SELECT STORE 
FROM TABLE_A
GROUP BY STORE
ORDER BY SUM(PRICE) DESC
LIMIT 1,1

Demo here.

If you want the price displayed too, you can just select that too;

SELECT STORE, SUM(PRICE) TOTAL_PRICE
FROM TABLE_A
GROUP BY STORE
ORDER BY TOTAL_PRICE DESC
LIMIT 1,1

Demo here.

Edit: If you have several most expensive stores and several second most expensive stores, the query to get the all the second most expensive ones becomes quite a bit more convoluted; I’m sure someone can beat the efficiency of this one;

SELECT STORE, SUM(PRICE) TOTAL_PRICE
FROM TABLE_A
GROUP BY STORE
HAVING TOTAL_PRICE =
  (SELECT SUM(PRICE) TMP 
   FROM TABLE_A 
   GROUP BY STORE
   HAVING TMP <
     (SELECT SUM(PRICE) TMP2
      FROM TABLE_A
      GROUP BY STORE
      ORDER BY TMP2 DESC
      LIMIT 1)
   ORDER BY TMP DESC LIMIT 1)

Demo here.