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Home/ Questions/Q 6724857
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T09:44:20+00:00 2026-05-26T09:44:20+00:00

I’m working on software which encrypts/decrypts files. I would like to be able to

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I’m working on software which encrypts/decrypts files.
I would like to be able to guess the length of the data after the encryption but I can’t use CryptoStream.Length (It throws a NotSupportedException).
Is there any way to guess it ?

I’m using RijndaelManaged (.Net Framework 4.0)

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  1. Editorial Team
    Editorial Team
    2026-05-26T09:44:20+00:00Added an answer on May 26, 2026 at 9:44 am

    This says it much better than I can
    https://web.archive.org/web/20120904015607/http://www.obviex.com/Articles/CiphertextSize.aspx

    From there:

    In the most generic case, the size of the ciphertext can be calculated as:

    CipherText = PlainText + Block – (PlainText MOD Block)

    where CipherText, PlainText, and Block indicate the sizes of the ciphertext, plaintext, and encryption block respectively. Basically, the resulting ciphertext size is computed as the size of the plaintext extended to the next block. If padding is used and the size of the plaintext is an exact multiple of the block size, one extra block containing padding information will be added.

    Let’s say that you want to encrypt a nine-digit Social Security Number (SSN) using the Rijndael encryption algorithm with the 128-bit (16-byte) block size and PKCS #7 padding. (For the purpose of the illustration, assume that dashes are removed from the SSN value before the encryption, so that "123-45-6789" becomes "123456789", and the value is treated as a string, not as a number.) If the digits in the SSN are defined as ASCII characters, the size of the ciphertext can be calculated as:

    CipherText = 9 + 16 – (9 MOD 16) = 9 + 16 – 9 = 16 (bytes)

    Notice that if the size of the plaintext value is the exact multiple of the block size, an extra block containing padding information will be appended to the ciphertext. For example, if you are to encrypt a 16-digit credit card number (defined as a 16-character ASCII string), the size of the ciphertext will be:

    CipherText = 16 + 16 – (16 MOD 16) = 16 + 16 – 0 = 32 (bytes)

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