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Asked: 2026-05-27T14:47:00+00:00

I’m working on some ancient Delphi code and I’ve come across something which I

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I’m working on some ancient Delphi code and I’ve come across something which I don’t quite understand.

[bla is set to 130245932]

outresult := ((bla * 1103516849) + 12359);

[outresult is equal to -413953101]

How does multiplying two positive numbers result in a negative number? And why is it that when I take the bla variable out of the equation and just use the integer directly (like this)

outresult := ((130245932 * 1103516849) + 12359);

I receive an error before the app even compiles

[DCC Error] Unit1.pas(60): E2099 Overflow in conversion or arithmetic operation

Some genius would be appreciated. Thanks.

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1 Answer

  1. Editorial Team

    Alright, I’ll make this an answer.

    The error message should be pretty clear. You have an integer overflow here:

    130245932 * 1103516849

    because 130245932 * 1103516849 = 143728580475708268 which is too large to fit into a 32-bit integer.

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