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Home/ Questions/Q 7780571
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:56:28+00:00 2026-06-01T18:56:28+00:00

I’m working on thread programming in java and i was stuck with a problem

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I’m working on thread programming in java and i was stuck with a problem where i have to execute 2 threads one after another. Below is the code snippet that abstracts my problem in brief.

class A{
  //default execute method of this class
  String a="thread1";
  String b="thread2";
  public void execute(){
    if(a=="thread1"){
       CreateThread1 t1 = new CreateThread1(this);
       t1.call();
    }
    else if(b=="thread2") {
      CreateThread1 t2 = new CreateThread1(this);
       t2.call();
    }
  }//end of execute
  public void UpdateUI(){
    try{
      Display.getDefault.asyncExec(new Runnable(){
        public void run(){
            //ui update code here
        }
      });
    }
    catch(SWTException e){
    }
  }   
}

Class CreateThread1{
    private A object;
    public CreateThread1(A object){
      this.object=object
    }
    public void call(){
      Thread t = new Thread(this);
      t.start();
    }
    public void run(){ 
      //business logic here 
       object.UpdateUI();//updates UI 
    }
}

Here class A is User Interface class which shows progress of the Thread task, in the above code CreateThread1 starts and CreateThread2 also starts even if CreateThread1 is not killed, i wish CreateThread2 to be triggered only after CreateThread1 finishes its task completely.Is it possible? Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T18:56:30+00:00Added an answer on June 1, 2026 at 6:56 pm

    You could use a FixedThreadPool with a size of 1. This will guarantee sequential execution.

    ExecutorService executor = Executors.newFixedThreadPool(1);
    executor.submit(runnable1);
    executor.submit(runnable2);
    executor.shutdown();
    executor.awaitTermination(10, TimeUnit.SECONDS); //waits until both runnables have finished.
    

    EDIT

    ExecutorService uses synchonrized structures internally so you can safely assume that runnable1 will run before runnable2.

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