Question

i’m working with a code they gave me to try to solve the errors, but until now, the Exception that is thrown only sends me to the line where the

log.error("Error saving data: " + e.toString());

is. i don’t know how to find out the correct line, because the e.printStackTrace() doesn’t output anything. The function is has this parts:

protected void processRequest(HttpServletRequest request, HttpServletResponse response)
        throws ServletException, IOException {...

try {...
} catch (Exception e) {

       e.printStackTrace();
       log.error("Error al almacenar los datos de usuario: " + e.toString());
    }

but in the middle i can’t find any reference to an exception. how can i get the “catch” part to show me where the error is?

Answer 1

you need to pass exceptions stackTrace to your logger. If you type e.printStackTrace() it puts stack trace to System.err

proper way is to write something,

log.error(“your message”,e);

and log4j will handle object e, and prints stackTrace in your logger.