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Home/ Questions/Q 6731419
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T10:31:35+00:00 2026-05-26T10:31:35+00:00

I’m working with a list of lists – let’s call it L – in

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I’m working with a list of lists – let’s call it L – in R, where the sub-lists are all the same length & padded with NAs. Ideally, I’d like to remove just the NA elements from each sublist, and one solution I’ve come up with is L <- lapply(L, na.omit). It seems to almost work; however, for each sub-list, the behavior is such that, for example,

[[1]]
[1] "0"     "12345"  "12346"  "12347" "12348"  "12349"  "12340"  "12341"  "12342" NA      NA          NA      NA      NA      NA     

[16] NA      NA      NA      NA      NA      NA      NA      NA      NA      NA      NA    

becomes

[[1]]
[1] "0"     "12345"  "12346"  "12347" "12348"  "12349"  "12340"  "12341"  "12342"
attr(,"na.action")
[1] 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
attr(,"class")
[1] "omit"

I’m a little bemused, to be honest – what’s up with the extra attr()s and such in my list? Is there a solution out there that won’t append them to the list? I’ve tried na.exclude, but it gives the same result. Is there something I’m missing? Thanks in advance : )

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  1. Editorial Team
    Editorial Team
    2026-05-26T10:31:36+00:00Added an answer on May 26, 2026 at 10:31 am

    No reason to be bemused… the Details section of ?na.omit says:

    If ‘na.omit’ removes cases, the row numbers of the cases form the
    ‘”na.action”’ attribute of the result, of class ‘”omit”’.

    Try subsetting each list element with is.na:

    L <- lapply(L, function(x) x[!is.na(x)])
    
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