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Editorial Team
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Asked: 2026-05-25T23:04:09+00:00

I’m working with a log file and I want to print from a specific

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I’m working with a log file and I want to print from a specific day till the end of it . that specific date is ($sd=27/Dec/2002) for example. now I want to search for this day and print from it till the end of log file ! but what if 27/Dec is not among items in log file ? it should search for items >= $sd (27/Dec) , how could I do this?

this code just search for $Sd which is 27/Dec/2002 , I want to search for items >= $sd

sed -n "$(awk '/'$sd'/ {print NR}' serverlog.log.log | head -1),$ p" serveerlog.log|cut -d: -f1

example of log file :

213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.132.36.66 - - [28/Dec/2002:19:33:29 +0100]

and the log file is sorted !

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1 Answer

  1. Editorial Team

    it would be very easy with awk. see the example below:

    kent$  cat log.txt
213.64.237.213 - - [20/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [20/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [20/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [20/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [20/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.132.36.66 - - [28/Dec/2002:19:33:29 +0100]

kent$  sd=21/Dec/2002




kent$  awk -F'[:[]' -v d=$sd '$2>d' log.txt

    output

    213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [23/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.64.237.213 - - [25/Dec/2002:03:02:22 +0100]
213.132.36.66 - - [28/Dec/2002:19:33:29 +0100]

    update

    try this awk line: $sd is the variable. hope that it would work for you.

    kent$  awk -F'[:[]' -v vd=$sd 'BEGIN{ gsub(/\//," ",vd);"date +%s -d \""vd"\""|getline d} {p=$0;  gsub(/\//," ",$2); "date +%s -d \""$2"\""|getline o;if(o>d) print p}' log.txt
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