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Home/ Questions/Q 7740095
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T08:41:14+00:00 2026-06-01T08:41:14+00:00

I’m working with a long running parfor loop in matlab. parfor iter=1:1000 chunk_of_work(iter); end

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I’m working with a long running parfor loop in matlab.

parfor iter=1:1000
   chunk_of_work(iter);
end

There are generally about 2-3 timing outliers per run. That is to say for every 1000 chunks of work performed there are 2-3 that take about 100 times longer than the rest. As the loop nears completion, the workers that evaluated the outliers continue to run while the rest of the workers have no computational load.

This is consistent with the parfor loop distributing work statically. This is in contrast with the documentation for the parallel computing toolbox found here:

“Work distribution is dynamic. Instead of being allocated a fixed
iteration range, the workers are allocated a new iteration only after
they finish processing their current iteration, which results in an
even work load distribution.”

Any ideas about what’s going on?

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  1. Editorial Team
    Editorial Team
    2026-06-01T08:41:15+00:00Added an answer on June 1, 2026 at 8:41 am

    I think the doc you quote has a pretty good description what is considered a static allocation of work: each worker “being allocated a fixed iteration range”. For 4 workers, this would mean the first being assigned iter 1:250, the second iter 251:500,… or the 1:4:100 for the first, 2:4:1000 for the second and so on.

    You did not say exactly what you observe, but what you describe is well consistent with dynamic workload distribution: First, the four (example) workers work on one iter each, the first one that is finished works on a fifth, the next one that is done (which may well be the same if three of the first four take somewhat longer) works on a sixth, and so on. Now if your outliers are number 20, 850 and 900 in the order MATLAB chooses to process the loop iterations and each take 100 times as long, this only means that the 21st to 320th iterations will be solved by three of the four workers while one is busy with the 20th (by 320 it will be done, now assuming roughly even distribution of non-outlier calculation time). The worker being assigned the 850th iteration will, however, continue to run even after another has solved #1000, and the same for #900. In fact, if there were about 1100 iterations, the one working on #900 should be finished roughly at the time when the others are.

    [edited as the orginal wording implied MATLAB would still assign the iterations of the parfor loop in order from 1 to 1000, which should not be assumed]

    So long story short, unless you find a way to process your outliers first (which of course requires you to know a priori which ones are the outliers, and to find a way to make MATLAB start the parfor loop processing with these), dynamic workload distribution alone cannot avoid the effect you observe.

    Addition: I think, however, that your observation that as “the loop nears completion, the worker*s* that evaluated the outliers continue to run” seems to imply at least one of the following

    1. The outliers somehow are among the last iterations MATLAB starts to process
    2. You have many workers, in the order of magnitude of the number of iterations
    3. Your estimate of the number of outliers (2-3) or your estimate of their computation time penalty (factor 100) is too low
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