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Home/ Questions/Q 8717699
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:21:40+00:00 2026-06-13T06:21:40+00:00

I’m working with data like this: Sample Detector Cq P_1 106 23.53152 P_1 106

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I’m working with data like this:

Sample  Detector        Cq
P_1   106    23.53152
P_1   106    23.152458
P_1   106    23.685083
P_1   135        24.465698
P_1   135        23.86892
P_1   135        23.723469
P_1   17  22.524242
P_1   17  20.658733
P_1   17  21.146122

As suggested in this post, I’m handling that with a MultiIndex. However, I’m wondering how, with such a structure, do some additional checks. Let’s explain better: each “Sample” column has a fixed number of repeated “Detector” elements, from 1 (no duplication) to several duplicated elements. I want to ensure that for each sample element, the number of detectors is always the same (i.e., if P_1 has 3 “106” detectors, P_2 should have 3 “106” detectors as well).

Currently I’m doing this rather crudely:

def replicate_counter(dataframe, name):
    subset = dataframe.ix[name]
    num_replicates = subset.index.size / subset.index.unique().size
    return num_replicates

# Further down...
# dataframe is a MultiIndex DataFrame like above
counts = pandas.Series([replicate_counter(dataframe, item[0]) for item
                        in dataframe.index]).unique()

if counts.size != 1:
    raise ValueError("Detectors not equal for all samples")

It seems very hacky to me and probably there are better ways to do this in pandas. How could this be accomplished?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:21:41+00:00Added an answer on June 13, 2026 at 6:21 am

    Turns out groupby is what is needed to make this clear and concise (and probably more efficient too):

    counts = dataframe.groupby(level=["Sample", "Detector"])
    counts = counts.size().unique()
    
    if counts.size != 1:
        raise ValueError("Detectors not equal for all samples")
    
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