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Home/ Questions/Q 7676821
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T17:17:07+00:00 2026-05-31T17:17:07+00:00

I’m working with Google GSON, and in the docs they mention they following: Object

  • 0

I’m working with Google GSON, and in the docs they mention they following:

Object Examples

class BagOfPrimitives {
  private int value1 = 1;
  private String value2 = "abc";
  private transient int value3 = 3;
  BagOfPrimitives() {
    // no-args constructor
  }
}

(Serialization)

BagOfPrimitives obj = new BagOfPrimitives();
Gson gson = new Gson();
String json = gson.toJson(obj);  
==> json is {"value1":1,"value2":"abc"}

Note that you can not serialize objects with circular references since that will result in infinite recursion.

(Deserialization)

BagOfPrimitives obj2 = gson.fromJson(json, BagOfPrimitives.class);   
==> obj2 is just like obj

At the very bottom, they use BagOfPrimitives.class. What does that do exactly? (I would imagine it might return the class, but in that case I’d expect the code just to omit the ‘.class’).

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  1. Editorial Team
    Editorial Team
    2026-05-31T17:17:09+00:00Added an answer on May 31, 2026 at 5:17 pm

    It’s a class literal – it gives a reference to the Class object representing the particular class. See section 15.8.2 of the JLS for more details. For example:

    String text = "Hello";
    Class<?> classFromObject = text.getClass();
    Class<?> classFromLiteral = String.class;
    System.out.println(classFromObject == classFromLiteral); // true
    

    In the case of the deserialization, it’s to tell the deserializer what type to use to try to deserialize the data as.

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