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Home/ Questions/Q 1053097
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T17:12:00+00:00 2026-05-16T17:12:00+00:00

Im working with PHP5, and I need to transform XML in the following form:

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Im working with PHP5, and I need to transform XML in the following form:

<section>
      <heading>
            <line absolutePage="4" page="2" num="35">A Heading</line>
      </heading>
      <subsection type="type1">
            <heading label="3">
                  <line absolutePage="4" page="2" num="36">A Subheading</line>
            </heading>
            <content/>
      </subsection>
</section>

Into something like this:

<section name="A Heading">
      <heading>
            <line absolutePage="4" page="2" num="35">A Heading</line>
      </heading>
      <subsection type="type1" label="3" name="A Subheading">
            <heading label="3">
                  <line absolutePage="4" page="2" num="36">A Subheading</line>
            </heading>
            <content/>
      </subsection>
</section>

Note that the label attribute has been been copied from the heading attribute to the parent element.

Also the text of the heading/line element has been added as an attribute of the heading parent node.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T17:12:00+00:00Added an answer on May 16, 2026 at 5:12 pm

    This stylesheet:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:template match="@*|node()">
            <xsl:copy>
                <xsl:apply-templates select="@*|node()"/>
            </xsl:copy>
        </xsl:template>
        <xsl:template match="subsection">
            <subsection label="{heading/@label}" name="{heading/line}">
                <xsl:apply-templates select="@*|node()"/>
            </subsection>
        </xsl:template>
        <xsl:template match="section">
            <section name="{heading/line}">
                <xsl:apply-templates select="@*|node()"/>
            </section>
        </xsl:template>
    </xsl:stylesheet>
    

    Output:

    <section name="A Heading">
        <heading>
            <line absolutePage="4" page="2" num="35">A Heading</line>
        </heading>
        <subsection label="3" name="A Subheading" type="type1">
            <heading label="3">
                <line absolutePage="4" page="2" num="36">A Subheading</line>
            </heading>
            <content></content>
        </subsection>
    </section>
    

    Note: Whenever is posible to use literal result elements and attributes value template, use it. That make code compact and fast. If you want more general answer, clarify that please.

    Edit: Missed section/@name. Of course, if empty string section/@label doesn’t bother you you could use section|subsection pattern matching.

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