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Home/ Questions/Q 6914319
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:19:56+00:00 2026-05-27T09:19:56+00:00

I’m working with some data in an Oracle 10g database, specifically bulk updating and

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I’m working with some data in an Oracle 10g database, specifically bulk updating and reading timestamp information. I had to convert from an MM/DD/YYYY HH24:MI:SS format to a YYYY-MM-DD HH24:MI:SS format because of business requirements. As well, the timestamp is stored as a VARCHAR instead of a native datetime due to business requirements.

Unfortunately, now I’m having trouble running select operations on my data.

Specifically, when I run the following select I receive ORA-01861: Literal does not match format string:

SELECT datetime_stamp 
  from entrytable 
where 
  to_date(datetime_stamp, 'YYYY-MM-DD HH24:MI:SS') 
  between 
     TO_DATE('11/27/2011 00:00:00', 'MM/DD/YYYY HH24:MI:SS') 
     and 
     TO_DATE('12/06/2011 23:59:59', 'MM/DD/YYYY HH24:MI:SS') 
  and rownum < 1000

I confirmed that the bad argument is to_date(datetime_stamp, ‘YYYY-MM-DD HH24:MI:SS’), but now I have 400k rows of data to parse to try and find the bad row.

Is there any way I can have Oracle return the row that is generating the ORA-01861 error?

I’ve tried using REGEXP_LIKE to find data that does not fit [0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9] [0-9][0-9]:[0-9][0-9]:[0-9][0-9], but all rows seem to fit that regular expression.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:19:57+00:00Added an answer on May 27, 2026 at 9:19 am
    create function td(s varchar2) return number is
    begin
      if to_date(s, 'YYYY-MM-DD HH24:MI:SS') is not null then return 1; end if;
      return null;
    exception
      when others then return 0;
    end;
    

    and then

    select datetime_stamp from entrytable where td(datetime_stamp) = 0
    
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