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Home/ Questions/Q 9219933
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T03:13:51+00:00 2026-06-18T03:13:51+00:00

I’m working with the below code to send emails to people in python. import

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I’m working with the below code to send emails to people in python.

import smtplib
from email.mime.multipart import MIMEMultipart, MIMEBase
from email.mime.text import MIMEText
from email.utils import formatdate

    def send_mail(send_from,send_to, subject, text, files=[], server = "localhost"):
        for s in send_to:
               COMMASPACE = ', '
               msg = MIMEMultipart()
               msg['From'] = send_from
               msg['To'] = COMMASPACE.join(s)
               msg['Date'] = formatdate(localtime=True)
               msg['Subject'] = subject

               msg.attach( MIMEText(text) )

               for f in files:
                       part = MIMEBase('application', "octet-stream")
                       part.set_payload( open(f,"rb").read() )
                       Encoders.encode_base64(part)
                       part.add_header('Content-Disposition', 'attachment; filename="%s"' %os.path.basename(f))
                       msg.attach(part)

               server = smtplib.SMTP(server)
               server.sendmail(send_from, s, msg.as_string())
               server.close()

Sorry for the formatting if it’s messed up. emails is a pre-defined list with two emails. The error I’m encountering is:
AttributeError: SMTP instance has no attribute ‘find’

Any idea? Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T03:13:52+00:00Added an answer on June 18, 2026 at 3:13 am

    You don’t need to create a separate email message for each recipient; just send a single message with multiple recipients:

    def send_mail(send_from,send_to, subject, text, files=[], server = "localhost"):
       msg = MIMEMultipart()
       msg['From'] = send_from
       msg['To'] = COMMASPACE.join(send_to)
    
       # ... 
    
       server = smtplib.SMTP(server)
       server.sendmail(send_from, send_to, msg.as_string())
       server.close()
    

    This is almost identical to the example “Here’s an example of how to send a MIME message containing a bunch of family pictures that may be residing in a directory” in the docs.

    (If you don’t want each person to see the other’s addresses, you can make them all BCCs instead of Tos.)

    If you’re more interested in what’s wrong with your original code, than with how to do it properly, there are two immediately visible problems:

    1. You’re joining each address, as Vader explains.
    2. You’re passing a single address as a string as the second argument to SMTP.sendmail, but the second argument is a sequence of addresses. To fix that, use [s] instead of s, as most of the examples do.

    Both of these are caused by the same confusion, treating each address as a list of addresses. You may have additional errors caused by the same problem.

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