Question

I’m writing a basic wordpress widget for my theme. I need to call my function inside the function widget. My function is located just outside the widget For example:

function my_function( $arg ) {
    ...
}

function widget( $args, $instance ) {
    my_function($arg);
}

and it will give me error

Fatal error: Call to undefined function my_function() in...

However if i place my_function inside the widget function, then it works. For example:

function widget( $args, $instance ) {

    function my_function( $arg ) {
        ...
    }

    my_function($arg);
}

I want to know why this would not work if it is placed outside the widget function? Thanks.

Answer 1

I think you may be in a PHP class (plugin class) when you declare your functions.

So try to modify your code like this :

function my_function( $arg ) {
    ...
}

function widget( $args, $instance ) {
    $ClassName->my_function($arg);
}

I think it might be better then!
Let me know!