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Asked: May 10, 20262026-05-10T15:14:18+00:00 2026-05-10T15:14:18+00:00

I’m writing a C parser using PLY, and recently ran into a problem. This

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I’m writing a C parser using PLY, and recently ran into a problem. This code:

typedef int my_type; my_type x; 

Is correct C code, because my_type is defined as a type previously to being used as such. I handle it by filling a type symbol table in the parser that gets used by the lexer to differentiate between types and simple identifiers.

However, while the type declaration rule ends with SEMI (the ‘;’ token), PLY shifts the token my_type from the second line before deciding it’s done with the first one. Because of this, I have no chance to pass the update in the type symbol table to the lexer and it sees my_type as an identifier and not a type.

Any ideas for a fix ?

The full code is at: http://code.google.com/p/pycparser/source/browse/trunk/src/c_parser.py Not sure how I can create a smaller example out of this.

Edit:

Problem solved. See my solution below.

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  1. 2026-05-10T15:14:18+00:00Added an answer on May 10, 2026 at 3:14 pm

    With some help from Dave Beazley (PLY’s creator), my problem was solved.

    The idea is to use special sub-rules and do the actions in them. In my case, I split the declaration rule to:

    def p_decl_body(self, p):     ''' decl_body : declaration_specifiers init_declarator_list_opt     '''     # <<Handle the declaration here>>          def p_declaration(self, p):     ''' declaration : decl_body SEMI      '''     p[0] = p[1] 

    decl_body is always reduced before the token after SEMI is shifted in, so my action gets executed at the correct time.

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