Question

Im writing a client/server app for android that sends a username and password to the server and receives a status for that user account.

My php code is like this:

$return['login'] = 'success';   
echo json_encode($return);

and the text received by android is:

{"login":"success"}

but I still get an error when I try to decode the json string to read the parameters:

JSONArray jsonArray = new JSONArray(input);

exception:

02-10 11:54:37.743: WARN/System.err(332): 
    org.json.JSONException: 
         Value {"login":"success"} of type org.json.JSONObject 
         cannot be converted to JSONArray
02-10 11:54:37.779: WARN/System.err(332): 
    at org.json.JSON.typeMismatch(JSON.java:107)

So I guess Im missing something that php should send, but after reading on json.org I just can’t see what it is. I have tried adding brackets before and after, as well as wrapping it in another array like this:

$parameters['login'] = 'success';   
    $return['parameters'] = $parameters;
echo json_encode($return);

Answer 1

You should be using JSONObject instead of JSONArray since you sending a key-value pair.