Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5975345
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T21:04:18+00:00 2026-05-22T21:04:18+00:00

I’m writing a custom View , but I can’t really figure out how to

  • 0

I’m writing a custom View, but I can’t really figure out how to use clipRect on a Canvas. I need this because I’m calling draw(Canvas) on another object and I’d like to give it my own (clipped) Canvas. My current solution is:

StaticLayout sl = new StaticLayout(text, tp, (int) (rect.right - rect.left), Alignment.ALIGN_NORMAL, 1f, 0f, true);

Bitmap layoutBitmap = Bitmap.createBitmap((int) (rect.right - rect.left), (int) (rect.bottom - rect.top), Config.ARGB_8888);
Canvas layoutCanvas = new Canvas(layoutBitmap);
sl.draw(layoutCanvas);

canvas.drawBitmap(layoutBitmap, null, rect, null);

However, this feels dirty, creating a new bitmap and a new canvas every time (I’m using this method to draw text in a box, see my previous question).

What I’d like to do is something like this:

StaticLayout sl = new StaticLayout(text, tp, (int) (rect.right - rect.left), Alignment.ALIGN_NORMAL, 1f, 0f, true);

canvas.save();
canvas.clipRect(rect, Region.Op.REPLACE);
sl.draw(canvas);
canvas.restore();

That “feels” much better, except that it doesn’t work. Am I using clipRect wrong? Do I not understand what it’s actually for or how to use it? Please advise.

P.S. My understanding of clipRect is that after that clipRect call, 0, 0 should actually translate to rect.left, rect.top.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T21:04:19+00:00Added an answer on May 22, 2026 at 9:04 pm

    After a bit of experimenting, it seems that clipRect only restricts drawing to the given rect, so that any draw calls outside that rect will be clipped to that rect. Thus, my understanding of clipRect was wrong.

    This means that, in order to use StaticLayout I’d have to first draw it to a Bitmap that is the size of my rect and then draw that Bitmap to my Canvas at the coordinates I need.

    However, I have resorted to using Canvas.drawText and TextPaint.breakText instead (so I don’t have to create a Bitmap everytime).

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a string like this: La Torre Eiffel paragonata all’Everest What PHP function
I'm parsing an RSS feed that has an ’ in it. SimpleXML turns this
I need to clean up various Word 'smart' characters in user input, including but
Does anyone know how can I replace this 2 symbol below from the string
I'm trying to decode HTML entries from here NYTimes.com and I cannot figure out
link Im having trouble converting the html entites into html characters, (&# 8217;) i
I want to count how many characters a certain string has in PHP, but
For some reason, after submitting a string like this Jack’s Spindle from a text
I am trying to understand how to use SyndicationItem to display feed which is
I have a jquery bug and I've been looking for hours now, I can't

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.