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Home/ Questions/Q 8900279
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:04:10+00:00 2026-06-15T01:04:10+00:00

I’m writing a function to choose a winner in a system based on majority.

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I’m writing a function to choose a winner in a system based on majority. If there’s no majority, then I need to remove the choice with the least votes and keep going until there is a winner with the majority of the votes. For example,

voting({'a':12, 'b':9, 'd':4})

In this case, 'a' has 12 votes, 'b' has 9, and 'd' has 4. Since 'a' does not have a majority (12/25 votes), I need to remove 'd' from the available choices, and it will have the majority (12/21). There may be any number of choices in each “ballot”, all that matters is the number one in each.

My code is for def voting(votes):

d = {}
winning_party = ''
i = 0
for key in votes.keys():
    d[key] = votes[key]
while winning_party == '':
    for key, vote in d.items():
        if d[key] > 0.5 * sum(d.values()):
            winning_party = key
            return winning_party
        else:
            if d[key] == min(d.values()):
                del d[key]

I’ve tried making minor changes but I either get an error that the dictionary changed in size during iteration, or the function stopped working.

Can anyone help me fix the code, or tell me how I can avoid changing the dictionary while it’s in the loop? I can only really use the code above, i.e. I can’t import anything or use anything other than basic functions.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T01:04:11+00:00Added an answer on June 15, 2026 at 1:04 am
    while winning_party == '':
        total_votes = sum(d.values())    # Recompute the total before each iteration.
        for key, vote in d.items():
            if d[key] > 0.5 * total_votes:
                winning_party = key
                return winning_party
    
        min_party = min(d, key=d.get)    # Find key having minimum votes.
        del d[min_party]                 # Delete it.
    
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