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Home/ Questions/Q 8443903
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T09:15:50+00:00 2026-06-10T09:15:50+00:00

I’m writing a grammar that supports arbitrary boolean expressions. The grammar is used to

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I’m writing a grammar that supports arbitrary boolean expressions. The grammar is used to represent a program, which is later passed through the static analysis tool. The static analysis tool has certain limitations so I want to apply the following rewrite rules:

Strict inequalities are approximated with epsilon:

expression_a > expression_b -> expression_a >= expression_b + EPSILON

Inequality is approximated using “or” statement:

expression_a != expression_b -> expression_a > expression_b || expression_a < expression_b

Is there any easy way to do it using ANTLR? Currently my grammar looks like so:

comparison          : expression ('=='^|'<='^|'>='^|'!='^|'>'^|'<'^) expression;

I’m not sure how to apply a different rewrite rule depending on what the operator is. I want to tree stay as it is if the operator is (“==”, “<=” or “>=”) and to recursively transform it otherwise, according to the rules defined above.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T09:15:52+00:00Added an answer on June 10, 2026 at 9:15 am

    […] and to recursively transform it otherwise, […]

    You can do it partly.

    You can’t tell ANTLR to rewrite a > b to ^('>=' a ^('+' b epsilon)) and then define a != b to become ^('||' ^('>' a b) ^('<' a b)) and then have ANTLR automatically rewrite both ^('>' a b) and ^('<' a b) to ^('>=' a ^('+' b epsilon)) and ^('<=' a ^('-' b epsilon)) respectively.

    A bit of manual work is needed here. The trick is that you can’t just use a token like >= if this token isn’t actually parsed. A solution to this is to use imaginary tokens.

    A quick demo:

    grammar T;
    
    options {
      output=AST;
    }
    
    tokens {
      AND;
      OR;
      GTEQ;
      LTEQ;
      SUB;
      ADD;
      EPSILON;
    }
    
    parse
     : expr
     ;
    
    expr
     : logical_expr
     ;
    
    logical_expr
     : comp_expr ((And | Or)^ comp_expr)*
     ;
    
    comp_expr
     : (e1=mult_expr -> $e1) ( Eq   e2=mult_expr -> ^(AND ^(GTEQ $e1 $e2) ^(LTEQ $e1 $e2))
                             | LtEq e2=mult_expr -> ^(LTEQ $e1 $e2)
                             | GtEq e2=mult_expr -> ^(GTEQ $e1 $e2)
                             | NEq  e2=mult_expr -> ^(OR ^(GTEQ $e1 ^(ADD $e2 EPSILON)) ^(LTEQ $e1 ^(SUB $e2 EPSILON)))
                             | Gt   e2=mult_expr -> ^(GTEQ $e1 ^(ADD $e2 EPSILON))
                             | Lt   e2=mult_expr -> ^(LTEQ $e1 ^(SUB $e2 EPSILON))
                             )?
     ;
    
    add_expr
     : mult_expr ((Add | Sub)^ mult_expr)*
     ;
    
    mult_expr
     : atom ((Mult | Div)^ atom)*
     ;
    
    atom
     : Num
     | Id
     | '(' expr ')'
     ;
    
    Eq    : '==';
    LtEq  : '<=';
    GtEq  : '>=';
    NEq   : '!=';
    Gt    : '>';
    Lt    : '<';
    Or    : '||';
    And   : '&&';
    Mult  : '*';
    Div   : '/';
    Add   : '+';
    Sub   : '-';
    Num   : '0'..'9'+ ('.' '0'..'9'+)?;
    Id    : ('a'..'z' | 'A'..'Z')+;
    Space : ' ' {skip();};
    

    The parser generated from the grammar above will produce the following:


    a == b

    enter image description here


    a != b

    enter image description here


    a > b

    enter image description here


    a < b

    enter image description here


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